3x^2-5x+3x-5=3x^2+4x-3x-4

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Solution for 3x^2-5x+3x-5=3x^2+4x-3x-4 equation:



3x^2-5x+3x-5=3x^2+4x-3x-4
We move all terms to the left:
3x^2-5x+3x-5-(3x^2+4x-3x-4)=0
We add all the numbers together, and all the variables
3x^2-2x-(3x^2+4x-3x-4)-5=0
We get rid of parentheses
3x^2-3x^2-2x-4x+3x+4-5=0
We add all the numbers together, and all the variables
-3x-1=0
We move all terms containing x to the left, all other terms to the right
-3x=1
x=1/-3
x=-1/3

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